C++ - VERY-EASY - PART004-Reverse Order - Print multiples of X from N to M

  Two numbers M and N are passed as the input. A number X is also passed as the input. The program must print the numbers divisible by X from N to M (inclusive of M and N).

Input Format:

The first line denotes the value of M

The second line denotes the value of N

The third line denotes the value of X

Output Format:

Numbers divisible by X from N to M, with each number separated by a space.

Boundary Conditions:

1 <= M <= 9999999

M < N <= 9999999

1 <= X <= 9999

Example Input/Output 1:

Input:

2

40

7

Output:

35 28 21 14 7

Example Input/Output 2:

Input:

66

121

11

Output:

121 110 99 88 77 66

CODE:

#include<stdio.h>

#include<stdlib.h>

int main()

{int a,b,c;

scanf("%d\n%d\n%d",&a,&b,&c);

int s=0;

for(int i=b;i>=a;i--)

{

if(i%c==0)

printf("%d ",i);

}

}