C++ very easy part 05 interlace odd/even from a to b

  Two numbers A and B are passed as input. The program must print the odd numbers from A to B (inclusive of A and B) interlaced with the even numbers from B to A.

Input Format: The first line denotes the value of A. The second line denotes the value of B.

Output Format: The odd and even numbers interlaced, each separated by a space.

Boundary Conditions: 1 <= A <= 9999999 A < B <= 9999999

Example Input/Output 1:

Input:

5

11


Output:

5 10 7 8 9 6 11


Explanation: The odd numbers from 5 to 11 are 5 7 9 11 The even numbers from 11 to 5 (that is in reverse direction) are 10 8 6 So these numbers are interlaced to produce 5 10 7 8 9 6 11


Example Input/Output 2:

Input:

4

14


Output:

14 5 12 7 10 9 8 11 6 13 4


Explanation: The odd numbers from 4 to 14 are 5 7 9 11 13 The even numbers from 14 to 4 (that is in reverse direction) are 14 12 10 8 6 4 So these numbers are interlaced to produce 14 5 12 7 10 9 8 11 6 13 4 (Here as the even numbers count are more than the odd numbers count we start with the even number in the output)


Example Input/Output 3:

Input:

3

12


Output:

3 12 5 10 7 8 9 6 11 4


Explanation: The odd numbers from 3 to 12 are 3 5 7 9 11 The even numbers from 12 to 3 (that is in reverse direction) are 12 10 8 6 4 So these numbers are interlaced to produce 3 12 5 10 7 8 9 6 11 4


Code:

#include<bits/stdc++.h>

using namespace std;
int main()

{

int i,n,m,j;

cin>>n>>m;

for(i=n,j=m;i<=m;i++,j--)

{

    if(i%2==1)
    cout<<i<<" ";

    

    if(j%2==0)
    cout<<j<<" ";

    

}

}